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Kevin Summersill · Answer 1 · 2019-04-19T18:05:56+0000

Due to we have total number of 6 carbons and one of them is the carboxylic group and we need to draw 2 methyl groups on the same carbon so the longest chain must be 4 carbons + 2 methyl branches and also these branches must be in carbon two and carbon three as follow:

Draw the structure(s) of the carboxylic acids with formula c6h12o2 that contain two-example-1

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