Question

Fill in the missing reactant and then balance each equation. k(s) + _____ → koh(aq) + h2(g) k (s) + 3h2o →2koh (aq) + 2h2 (g) bi(no3)3(aq) + _____ → bi2s3(s) + hno3(aq) hno3(aq) + _____ → ba(no3)2(aq) + h2o(l)

Answer 1

Filled missing reactant and balanced equation

2K(s)+ 2H2O(l) ---> 2 KOh(aq) + H2 (g)

2Bi(No3)3(aq) + 3H2S(g)----> Bi2S3 + 6 HNO3(aq)

2HNO3(aq) +Ba(OH)2(aq) ----> Ba(NO3)2 (aq) + 2H2O(l)

in equation above the missing reagent in first equation is H20, second is h2S while the third is Ba(OH)2

Answer 2

1) 2K(s) + 2H₂O(l)→ 2KOH(aq) + H₂(g)
This is a single replacement reaction where K reacts with H₂O , displaces the H⁺ ion in water and combines with OH⁻ to form a base.

2) 2Bi(NO₃)₃(aq) + 3H₂S(g)→ Bi₂S₃(s) + 6HNO₃(aq)
This is a double displacement reaction where the ions are exchanged and form new compounds. Since ions are exchanged between 2 compounds its called double displacement.

3) 2HNO₃(aq) + Ba(OH)₂ → Ba(NO₃)₂(aq) + 2H₂O(l)
This is an acid base reaction where nitric acid and barium hydroxide react to form the respective salt and water