60.6k views
25 votes
Derivatives of cos2x+1 / sin2x ?​

User Manolowar
by
8.6k points

1 Answer

5 votes

Answer:

Since we know that,

cos2x= cos²x-sin²x=(cosx-sinx)(cosx+sinx)

And, sin2x=2sinx.cosx

Therefore,

1-sin2x= cos²x+sin²x-2sinx.cosx

1-sin2x= (cosx-sinx)²

Then let

y=cos2x/(1-sin2x)

User Hhh
by
8.1k points

Related questions

asked Nov 17, 2024 182k views
Jack Zach Tibbles asked Nov 17, 2024
by Jack Zach Tibbles
7.8k points
1 answer
2 votes
182k views
1 answer
3 votes
180k views
1 answer
4 votes
134k views