Question

Ten percent of cereal boxes have a prize. A student wants to estimate the probability that when 8 boxes are purchased, fewer than 3 have a prize.

To do this, the student uses a random number table to pick 8 numbers from 0 to 9. She lets 0 represent a box with a prize and 1 through 9 represent a box without a prize. She repeats this for a total of 12 trials. The results are shown in the table.

65720797 56708801 96902111 61803079 80659604 01609960
35904439 31413140 16206837 49947066 65431196 99141179
Select from the drop-down menus to correctly complete each statement.

To estimate the probability that fewer than 3 out of 8 boxes have a prize, the student must count the number of trials with and divide by the number of trials.

This gives an estimated probability of about .

Answer 1

The first drop down to finish it is: To estimate the probability that fewer than 3 out of 8 boxes have a prize, the student must count the number of trials with fewer than three 0s and divide by the number of trials.

For the second one: This gives an estimated probability of about 0.92.

This is confirmed because I took the test. Hope this helps ;)

Answer 2

The experiment consists of 12 trial where 8 number is drawn in every trial. Since number 0 means a box with a prize, then fewer than 3 prize means less than 3 occurrences. The interpretation of the result would be:

65720797 = true
56708801 = true
96902111 = true
61803079 = true
80659604 = true
01609960= FALSE, three occurrences of 0
35904439 = true
31413140 = true
16206837 = true
49947066 = true
65431196 = true
99141179= true

The result is that there are 11 true conditions out of 12 trial. Then, the estimated probability would be 11/12= 91.67%