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The lengths of trout in a lake are normally distributed with a mean of 30 inches and a standard deviation of 4.5 inches. Enter the z-score of a trout with a length of 28.2 inches.

User Pankijs
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1 Answer

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The z-score would be -0.4.

The formula for z-scores is


z=(X-\mu)/(\sigma)

Using our information, we have:

z=(28.2-30)/(4.5)= (-1.8)/(4.5)=-0.4
User William Madede
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