Answer:
![\boxed {\boxed {\sf About \ 1.040 \ moles \ of \ nitrogen }}](https://img.qammunity.org/2022/formulas/chemistry/high-school/yykdabmgc0mstgphalvcjjz9q69jyfgzhk.png)
Step-by-step explanation:
To convert from grams to moles, we must use the molar mass. This can be found on the Periodic Table. We have a sample of nitrogen, so look for N on the table.
- Nitrogen (N): 14.007 g/mol
Now, use this molar mass as a ratio.
![\frac {14.007 \ g \ N }{1 \ mol \ N }](https://img.qammunity.org/2022/formulas/chemistry/high-school/4cq0h8nvq9eoyg481g0csi9ul0k7m882c7.png)
Multiply by the number of grams in the sample (14.57)
![14.57 \ g \ N *\frac {14.007 \ g \ N }{1 \ mol \ N }](https://img.qammunity.org/2022/formulas/chemistry/high-school/34tmcbyc4f57x055bpxxb1sdo7qt06u7wq.png)
Flip the fraction so the grams of nitrogen will cancel.
![14.57 \ g \ N *\frac {1 \ mol \ N }{14.007 \ g \ N}](https://img.qammunity.org/2022/formulas/chemistry/high-school/2zoc3drle7ngjaddx9r41h5vxnrz5hi704.png)
![14.57 *\frac {1 \ mol \ N }{14.007 }](https://img.qammunity.org/2022/formulas/chemistry/high-school/hn0snn047vhpy8xrzi1e1dimz4pw2n7a0r.png)
![\frac {14.57 \ mol \ N }{14.007 }](https://img.qammunity.org/2022/formulas/chemistry/high-school/8absckky8uc8tcyhw0udzk8e14hgdcz75w.png)
![1.04019419 \ mol \ N \\](https://img.qammunity.org/2022/formulas/chemistry/high-school/nri9vlwyph9a97bhe91et8ieo4zn07gwv3.png)
The original measurement of grams had 4 significant figures, so we need to round our answer to the same number of sig figs.
For the number we calculated, that is the thousandth place. The 1 in the ten thousandth place tells us to keep the 0 in the thousandth place.
![1.040 \ mol \ N](https://img.qammunity.org/2022/formulas/chemistry/high-school/sra1n32dfgyl0os1j208h205w302bthqht.png)
There are about 1.040 moles of nitrogen in 14.57 grams.