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If a line crosses the y-axis at (0, 1) and has a slope of ,4/5 what is the equation of the line? 4y − 5x = 5 y − 4x = 5 5y + 4x = 5 5y − 4x = 5
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If a line crosses the y-axis at (0, 1) and has a slope of ,4/5 what is the equation of the line?

4y − 5x = 5

y − 4x = 5

5y + 4x = 5

5y − 4x = 5

User Nmore
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1 Answer

1 vote
y = mx + b.
m = slope
b = y-intercept
y = (4/5)x + 1
5(y - (4/5)x = 1)
5y - 4x = 5
So the answer is
D) 5y - 4x = 5
User Igor Gladun
by
8.3k points
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