Find the sum of the first 10 terms of the geometric sequence 12000 1200 120 12 1.2

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BhalchandraSW · Answer 1 · 2019-01-06T23:33:15+0000

1, -4, -9, -14, this is arithmetic sequencewith difference =d = -5 a12 = a1 +(n-1) d =1 +(12-1)(-5) = 1+(11)(-5) = 1 -55 = -54 sum of the first 12 terms =( n/2 ) * (a1 +a12) =12/2 (1-54) =6(-53) =-318

Find the sum of the first 10 terms of the geometric sequence 12000 1200 120 12 1.2

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