Question

An aqueous solution has an h3o+ concentration of 4.4×10-2 m. calculate [oh–] for this solution.

Answer 1

first calculate Ph
Ph= -log (H3O+)
Ph=-log( 4.4 x10^-2)= 1.4

Ph +Poh=14
Poh is therefore= 14 - 1.4=12.6

Oh- concentration is calculated as follows
1 x10^ -POh
that is 1 x10^-12.6 which is= 2.5 x10^-13