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Solve a0 = 1, and an = 2an−1 + 1 for n ≥ 1 using the characteristic equation method. hint: try an = a, a constant, to find a particular solution.
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Mar 4, 2019
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Solve a0 = 1, and an = 2an−1 + 1 for n ≥ 1 using the characteristic equation method. hint: try an = a, a constant, to find a particular solution.
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Given that an=2an-1, to solve for a0=1, we substitute the value of a0 in the equation as follows:
a0=2*1-1+1
a0=2-1+1
a0=3-1
a0=2
the answer is 2
Phizzy
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Mar 10, 2019
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