Question

Can you find the magnetic field based on force? a straight segment of wire 35.0 cm long carrying a current of 1.40 a is in a uniform magnetic field. the segment makes an angle of 53° with the direction of the magnetic field. if the force on the segment is 0.20 n, what is the magnitude of the magnetic field?

Answer 1

The force exerted by a magnetic field on a wire carrying current is:

where I is the current, L the length of the wire, B the magnetic field intensity, and the angle between the wire and the direction of B.

In our problem, the force is F=0.20 N. The current is I=1.40 A, while the length of the wire is L=35.0 cm=0.35 m. The angle between the wire and the magnetic field is , so we can re-arrange the formula and substitute the numbers to find B:

Answer 2

The force exerted by a magnetic field on a wire carrying current is:

`F=ILB \sin \theta`
where I is the current, L the length of the wire, B the magnetic field intensity, and
`\theta` the angle between the wire and the direction of B.

In our problem, the force is F=0.20 N. The current is I=1.40 A, while the length of the wire is L=35.0 cm=0.35 m. The angle between the wire and the magnetic field is
`53 ^(\circ)`, so we can re-arrange the formula and substitute the numbers to find B:

`B= (F)/(IL \sin \theta)= (0.20 N)/((1.40 A)(0.35 m)(\sin 53^(\circ)))=0.51 T`