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5 votes
A 60 kg driver gets into an empty taptap to start the day's work. the springs compress 1.5Ã10â2 m . what is the effective spring constant of the spring system in the taptap?

User RojoSam
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1 Answer

5 votes
The force applied to the spring is the weight of the driver:

W=mg=(60 kg)(9.81 m/s^2)=588.6 N
Under this force, the spring compresses by
x=1.5 \cdot 10^(-2)m. We can find the spring's constant k by using Hook's law:

F=kx
And so

k= (F)/(x)= (588.6 N)/(1.5 \cdot 10^(-2)m)=39240 N/m
User David Alsh
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