Question

12. What is the equation in point-slope form of the

line that passes through the points (2, -3) and (-5, 8)?

Answer 1

⇒First step is to find the gradient

`m=(y_(2) -y_(1) )/(x_(2)-x_(1) ) \\m=(8-(-3))/(-5-2) \\m=(8+3)/(-7) \\m=-(11)/(7)`

In the general equation y=mx+c let us find the value of c by plugging in the known values

I will use the point (-5,8) Note you can use any .You will get the same value of c.

`8=-(11)/(7) (-5)+c\\8=(55)/(7) +c\\c=8-(55)/(7) \\c=(1)/(7)`

The equation now is:

`y=-(11)/(7) x+(1)/(7)`