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If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2
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If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2

User Synesso
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2 Answers

3 votes
The answer is 4*sqrt(8)
Attached is my work.
If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2-example-1
User Dan Billings
by
8.4k points
3 votes
(a+b)^2= a^2+b^2 +2ab
= 16 + 2 (8)
= 16 + 16
= 32
User Kevin Watson
by
7.8k points
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