Answer: Famke uses her phone for 10 minutes and she charge it for 20 minutes .
Explanation:
Let x be the number of hours Famke charges her phone.
Let y be the number of hours Famke uses her phone.
According to question, he charged it for twice the amount of time she used it.
So, it becomes
![x=2y\\\\x-2y=0-----(1)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/lf7isqvjbuweey1tkzo465u7lr366odbj4.png)
Number of points he gain while charging her phone = 2%
Number of points he loses while used her phone = 5%
Total points he lost = 10%
So, our equation would be
![0.02x-0.05y=-0.10-----(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/6f1ki6l80mo1xm8eoxtv2o1ksuagd0jxxt.png)
Put the value of x in the eq(2).
![0.02* 2y-0.05y=-0.10\\\\0.04y-0.05y=-0.10\\\\-0.01y=-0.10\\\\y=10](https://img.qammunity.org/2019/formulas/mathematics/middle-school/469dprq7oeo8fdp18cr9es06ovaogtv8vk.png)
and x=2×10=20 minutes
Hence, Famke uses her phone for 10 minutes and she charge it for 20 minutes.