Question

What is the ph of a buffer that consists of 0.45 m ch3cooh and 0.35 m ch3coona?

Answer 1

Hello!

The pH of a buffer that consists of 0,45 M CH₃COOH and 0,35 M CH₃COONa can be calculated using the Henderson-Hasselbach equation. To input the values into this equation, we'll need the pKa of CH₃COOH, which can be found in tables. This value is 4,75. The Henderson-Hasselbach equation is as follows:


`pH=pKa + log( ([A^(-) ])/([HA]) ) \\ pH=4,75 + log( (0,35 M)/(0,45M) ) \\ pH=4,64`

So, the pH of such buffer would be 4,64.

Have a nice day!