Question

What mass, in grams, of sodium bicarbonate, nahco3, is required to neutralize 1000.0 l of 0.350 m h2so4?

Answer 1

Hello!

The net chemical equation between Sodium Bicarbonate and H₂SO₄ is the following one:

2NaHCO₃ + H₂SO₄ → Na₂SO₄ + 2H₂O + 2CO₂

To calculate the amount of Sodium Bicarbonate needed to neutralize 1000 L of 0,350 M H₂SO₄ we'll need to use the following conversion factor, to go from the volume of H₂SO₄ to grams of Sodium Bicarbonate:


`1000 L H_2SO_4* (0,350 moles H_2SO_4)/(1 L)* (2 moles NaHCO_3)/(1 mol H_2SO_4)* (84,007gNaHCO_3)/(1molNaHCO_3) \\ \\ =58804,9 g NaHCO_3`

So, to neutralize 1000 L of 0,350 moles of H₂SO₄ you'll need 58804,9 grams of NaHCO₃