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30 votes
30 votes
A paper company is designing a new, pyramid-shaped paperweight. Its development team has decided

that to make the width of the paperweight 4 inches less than the length and the height of the
paperweight 3 inches less than the length. The paperweight must have a volume of 12 cubic inches.
What are the dimensions of the paperweight?
The width is
inches, the length is
inches, and the height is
inches

User Petrik De Heus
by
2.9k points

2 Answers

16 votes
16 votes

Final answer:

To find the dimensions of the pyramid-shaped paperweight with a given volume of 12 cubic inches, you need to solve for the length using the formula for the volume of a rectangular pyramid, and from there, calculate the width and height as they are defined relative to the length.

Step-by-step explanation:

The student's question requires solving for the dimensions of a pyramid-shaped paperweight given its volume and the relationship between its length, width, and height. Since the paper company team has decided that the width of the paperweight is 4 inches less than the length (L) and the height of the paperweight is 3 inches less than the length, we can represent the width as (L - 4) inches and the height as (L - 3) inches. The volume of a rectangular pyramid is given by the formula V = (1/3) x length x width x height.

Given the volume (V) is 12 cubic inches, we can set up the equation:

12 = (1/3) x L x (L - 4) x (L - 3)

By solving this equation, we find the dimensions that satisfy the volume requirement for the paperweight.

User Striatum
by
2.9k points
19 votes
19 votes

Answer:

4x+3=12

Step-by-step explanation:

User Nayrb
by
3.1k points