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How many grams of N2 are required to produce 100.0 l 0f NH3 at STP?

User PeeS
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2 Answers

4 votes
it is 62.5g N2--------------
User Jmaloney
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The ideal gas equation is PV = nRT. n = PV/RT n =
(1 atm)(100 L)/(0.08206 L-atm/mol-K)(273K)
n = 4.46 mol of NH3,we need 2 moles of NH3 to get 1 mole of N2 4.46 mol NH3 so
(1 mol N2/2 mol NH3) = 2.23 moles N2 2.23 moles of N2(28 g N2/1 mol N2) =

Answer is 62.5g N2

User Anuradha Fernando
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