145k views
0 votes
1)

Write an equation in point-slope form for the line through (5, 7) and (6, 8).
Please show your work!
(Hint: Find the slope. Then, use y - y1 = m (x - x1) )



2)
Write an equation in point-slope form for the line through (-3, 6) and (3, -6).
Please show your work!
(Hint: Find the slope. Then, use y - y1 = m (x - x1) )

User Jstaab
by
6.0k points

1 Answer

5 votes
◆ Straight Lines ◆

Heya !


1) \: line \: is \: passing \: through \:points \: (5,7) \: and \: (6,8) \\ \\ slope \: of \: line \: = ((y2 - y1))/((x2 - x1)) \\ \\ slope \: = \: ((8 - 7))/((6 - 5)) = \: 1 \\ \\ equation \: of \: line \: = \: (y - y1) \: = m (x - x1) \\ \\ equation \: of \: line \: =( y - 7) = 1(x - 5) \\ \\ equation \: of \: line \: - \\ x - y + 2 = 0 \: ans. \\ \\ \\ 2) \: line \: is \: passing \: through \: ( - 3,6) \: and \: ( 3, - 6) \\ \\ slope \: of \: line \: = ((y2 - y1))/((x2 - x1)) \\ \\ slope \: of \: line \: = (( - 6 - 6))/((3 - ( - 3))) = - 2 \\ \\ equation \: of \: line = (y - y1) = m(x - x1) \\ \\ equation \: of \: line \: = (y - 6) = - 2(x + 3) \\ \\ equation \: of \: line \: - \\ 2x + y = 0 \: ans. \\ \\ hope \: it \: helps \: you :)

◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆
User Hilnius
by
6.1k points