2 Answers

Samnaction · Answer 1 · 2019-07-21T13:11:15+0000

Answer:

$\text{The roots are }(4)/(5)\pm (√(26))/(5)$

Explanation:

Given the equation

5y^2-8y=2

we have to solve the above equation using quadratic formula

5y^2-8y-2=0

$\text{Comparing above equation with the standard equation }ax^2+bx+c=0\text{ , we get}$

a=5, b=-8, c=-2

By quadratic formula the solution is

$y=(-b\pm√(b^2-4ac))/(2a)$

$y=(8\pm √((-8)^2-4(5)(-2)))/(2(5))$

$y=(8\pm √(104))/(10)$

$y=(4)/(5)\pm (2√(26))/(10)=(4)/(5)\pm (√(26))/(5)$

$\text{The roots are }(4)/(5)\pm (√(26))/(5)$

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