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John is playing a gamr of darts. The probability that he throws a dart into the center of the dart board (bulls eyes) is 1/10. The probability tgat he throws rhe dart the dart into the dart into the 10 point ring is 3/10. What is the probability that he either hits a bullseye or scores 10 points?

2 Answers

5 votes

Answer:

2/5

Explanation:

User JoLoCo
by
7.4k points
3 votes

Answer:


\bf\textbf{The probability that he either hits a bulls eye or scores 10 points = }(2)/(5)

Explanation:


\text{The probability that he throws a dart into the center of the dart board = }(1)/(10)


\text{The probability that he throws the dart into the 10 point ring = }(3)/(10)

Now we need to find the probability that he either hits a bulls eye or scores 10 points.

The probability that he either hits a bulls eye or scores 10 points = Probability that he hits the bulls eye + Probability that he throws the dart into the 10 point ring


\text{The probability that he either hits a bulls eye or scores 10 points = }(1)/(10)+(3)/(10)


\text{The probability that he either hits a bulls eye or scores 10 points = }(4)/(10)


\bf\textbf{The probability that he either hits a bulls eye or scores 10 points = }(2)/(5)

User RKumsher
by
6.4k points
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