Question

Match the expressions with the nonpermissible replacements for y

Answer 1

-7 _D_

`(3)/(2)` _A_

1 _C_

`(-1)/(4)` _B_

_A_
`(y^(2) -2y+1)/(2y-3)`

_B_
`(y(y+5))/(4y+1)`

_C_
`(5y^(2)-6y+1 )/(-5(y-1))`

_D_
`(y^(2)-y-6 )/(-2(y+7))`

Answer 2

-7 →
`(y^2-y+6)/(-2(y+7))`

3/2 →
`(y^2-2y+1)/(2y-3)`

1 →
`(5y^2-6y+1)/(-5(y-1))`

-1/4 →
`(y(y+5))/(4y+1)`

Explanation:

We need to find the nonpermissible replacements for y.

Equate the denominator of each expression equal to 0, to find the nonpermissible replacements for y.

First expression is

`(y^2-2y+1)/(2y-3)`

Equate (2y-3) equal to 0.

`2y-3=0`

Add 2 on both sides.

`2y=3`

Divide both sides by 3.

`y=(3)/(2)`

Therefore, 3/2 is the nonpermissible replacements for y.

Second expression is

`(y(y+5))/(4y+1)`

Equate (4y+1) equal to 0.

`4y+1=0`

`4y=-1`

`y=-(1)/(4)`

Therefore, -1/4 is the nonpermissible replacements for y.

Third expression is

`(5y^2-6y+1)/(-5(y-1))`

Equate -5(y-1) equal to 0.

`-5(y-1)=0`

`y-1=0`

`y=1`

Therefore, 1 is the nonpermissible replacements for y.

Fourth expression is

`(y^2-y+6)/(-2(y+7))`

Equate -2(y+7) equal to 0.

`-2(y+7)=0`

`y+7=0`

`y=-7`

Therefore, -7 is the nonpermissible replacements for y.