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2 h2o ( g) 2 h2 (g) + o2 (g) kp = 7.8 × 10-16 at 930 k. give the value of kp for this reaction, if it is written as: 1/2o2 (g) + h2 (g) h2o (g)

1 Answer

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When multiplying by a constant, raise Kp to the power of that constant.

When the reaction is reversed, it gives the inverse of Kp.

Kp^(-1/2) = (7.8 x 10^-16)^(-1/2) = 3.6 x 10^7
User Abhinav Sharma
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