Question

100 point question!! A driver begins to brake when her car is traveling at 15.0 m/s, and the car comes to a stop 4.0 s later. How much farther does the car go after the driver begins to brake, assuming constant acceleration?

Answer 1

the answer should be 30 m

Step-by-step explanation:

have a good day

Answer 2

30 m

Step-by-step explanation:

Let's list out the known variables that we are given in this question.

• v₀ = 15 m/s
• v = 0 m/s
• t = 4 s

We are trying to solve for displacement in the x-direction.

• Δx = ?

Find which constant acceleration equation contains all 4 of these variables.

• 
  `\displaystyle \triangle x = \Big ((v+v_0)/(2) \Big ) t`

Plug the known values into the equation and solve for delta x.

• 
  `\displaystyle \triangle x = \Big ((0+15)/(2) \Big ) \cdot 4`
• 
  `\displaystyle \triangle x = \Big ((15)/(2) \Big ) \cdot 4`
• 
  `\displaystyle \triangle x =(60)/(2)`
• 
  `\triangle x = 30`

The car goes 30 m after the driver begins to brake.