Question

Which equation represents an interaction of a weak base with water? naoh(aq) na + (aq) + oh1- (aq) ch3ch2oh(l) ch3ch2oh(aq) n2h4(aq) + h2o(l) n2h5 + (aq) + oh1- (aq) hpo42-(aq) + h2o(l) po43-(aq) + h3o + (aq) h2o h+ + oh-?

Answer 1

C. N2H4(aq)+H2O(I)<==>N2H5+(aq)+OH1-(aq)

Step-by-step explanation:

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Answer 2

Reactions:
1) NaOH(aq)==>Na+(aq)+OH^1-(aq)
2) CH3CH2OH(I)==>CH3CH2OH(aq)
3) N2H4(aq)+H2O(I)<==>N2H5+(aq)+OH1-(aq)
4) HPO4^2-(aq)+H2O(I)<==> PO4^3-(aq)+H3O+(aq)
5) H2O <==> H+ + OH-
Answer is: 3) N2H4(aq)+H2O(I)<==>N2H5+(aq)+OH1-(aq).
According to Bronsted-Lowry theory acid are donor of protons and bases are acceptors of protons (the hydrogen cation or H⁺). In this reaction N₂H₄ accepted proton and become conjugate acid N₂H₅⁺. Sodium hydroxide is strong base.