Question

Calculate how to prepare 250.00 ml of approximately 1.0 m hcl solution from the 2.5 m hcl solution. show your work.

Answer 1

250.00 mL) x (1.0 M ) / (2.5 M) = 100 mL

So take 100 mL of 2.5 M HCl and dilute it to 250 mL.

Answer 2

Answer: Add 150 ml of water to 100 ml of 2.5 M stock solution.

Explanation: According to the neutralization law,

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of stock solution = 2.5 M

`V_1` = volume of stock solution = ?

`M_2` = molarity of desired solution = 1.0 M

`V_2` = volume of desired solution = 250 ml

Now put all the given values in the above law, we get the volume of stock solution.

`(2.5M)* V_1=(1.0M)* (250ml)`

`V_1=100ml`

Therefore, 100 ml of 2.5 M of stock solution is taken and 150 ml of water is added to make the volume to 250 ml.