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If the change in enthalpy is -5074.1 kj , how much work is done during the combustion?
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Jan 9, 2019
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If the change in enthalpy is -5074.1 kj , how much work is done during the combustion?
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Wilber
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Hence,
∆H = ∆U + W
=>
W = ∆H - ∆U
= -5074 kJ - (-5084.) kJ
= 10 kJ
Jbchichoko
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Jan 15, 2019
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