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Write an equation of the line through (6,-2) and (-3,1)

User Jmend
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1 Answer

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\underline {Find \ the \ slope:}


\Bigg( Slope = (y_2-y_1)/(x_2-x_1) \Bigg)


Slope = (1-(-2))/(-3-6)


Slope = - (1)/(3)


\Bigg(Equation: y = mx + c} \Bigg)


\underline{Insert \ slope:}


Equation: y = - (1)/(3)x + c


\underline {Find \ y-intercept}


at \ point (-3, 1)


1 = - (1)/(3) (-3) + c


c= 0


\underline {Insert \ y-intercept:}


Equation: y = - (1)/(3)x


\boxed { \boxed {Ans: y = - (1)/(3) x}}
User Hydro
by
6.7k points
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