49.1k views
3 votes
If a rectangle's length is 7 more than 4 times the width and the perimeter is 54 what are the dimensions of the rectangle?

User Yatiac
by
7.8k points

1 Answer

5 votes
let w = width of the rectangle
4w+7 = length of the rectangle

perimeter = 2 lengths + 2 widths

2w + 2(4w+7) = 54
2w + 8w + 14 = 54
10w = 40
w = 4
4w+7 = 23

dimensions of rectangle:
width = 4
length = 23 hope this helps
User Tim Bish
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories