Question

If f(x)=3x^2+2 and g(x)=x^2-9 find (f-g)(x)

Answer 1

The answer would be 2x²+11.

(f-g)(x)=f(x)-g(x)=3x²+2-(x²-9) = 3x²- x² + 2 --9 = 2x²+2+9 = 2x²+11

Answer 2

Here given,
`f(x) = 3x^2+2` and
`g(x) = x^2-9`

we have to find
`(f-g)(x)` which means the subtracting of the functions f(x) and g(x).

`(f-g)(x) = f(x) - g(x)`

=
`(3x^2+2) - (x^2-9)`

=
`3x^2+2 -x^2-(-9)`

=
`3x^2-x^2+2+9` ( we know that multiplication of negative and negative is positive)

=
`2x^2+2+9`

=
`2x^2+11`

We have got the required answer here.

`(f-g)(x) = 2x^2+11`