Question

What is the area of this figure?



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Answer 1

`\huge \boxed{\sf 42\ sq.\ blocks} \\\\\\\sf Break\ the\ composite\ shape\ into\ equal\ triangles\ and\ a\ rectangle.\\\\\displaystyle 2 * Area\ of\ a\ triangle =2 * (bh)/(2) =2 *(7 * 2)/(2)=14 \\\\ Area\ of\ a\ rectangle = bh=4 * 7=28\\\\Sum\ of\ the\ areas=14+28=42`

Answer 2

`Area \ of \ top \ triangle = (1)/(2) * base * height`

`\boxed{(1)/(2) * 7 * 2 = 7 cm^(2) }`


`Area \ of \ the \ rectangle = length * width`

`\boxed {7 * 4 = 28 cm^2}`


`Area \ of \ bottom \ triangle = (1)/(2) * base * height`

`\boxed {(1)/(2) * 7 * 2 = 7 cm^(2)}`


`\boxed{\boxed{Total \ area = 7 + 28 + 7 = 42 cm^2}}`