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The equation for the circle is: x^2+y^2−12x+6y−19=0 . What is the center of the circle? Question 12 options: (-6, 3) (12, -6) (6, -3) (-12, 6)
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The equation for the circle is: x^2+y^2−12x+6y−19=0 . What is the center of the circle? Question 12 options: (-6, 3) (12, -6) (6, -3) (-12, 6)
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Aug 10, 2019
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The equation for the circle is:
x^2+y^2−12x+6y−19=0 .
What is the center of the circle?
Question 12 options:
(-6, 3)
(12, -6)
(6, -3)
(-12, 6)
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Andreak
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Andreak
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The answer would be ( -12, 6 ) try plugging in answers into the problem
Bhagyesh Dudhediya
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Aug 15, 2019
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Bhagyesh Dudhediya
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