Question

The center of a circle is at (–10, 6) and it has a radius of 4. What is the equation of the circle?

Question 9 options:

(x – 10)^2 + (y + 6)^2 = 2


(x – 10)^2 + (y + 6)^2 = 16


(x + 10)^2 + (y – 6)^2 = 2


(x + 10)^2 + (y – 6)^2 = 16

Answer 1

[x-(-10)]²+(y-6)²=4²
the answer is (x + 10)^2 + (y – 6)^2 = 16

Answer 2

The equation of circle is given by :

`(x-h)^(2) + (y-k)^(2) = r^(2)`

where,

(h,k) is the center of circle and r is radius of circle.

Now we are given :

Center (h,k) as (-10,6) and radius as 4

Plugging these values in the equation ,

`(x-(-10))^(2) + (y-6)^(2) = 4^(2)`

So equation of circle with center at (-10,6) and radius 4 is given by:

`(x+10)^(2) + (y-6)^(2) = 16`