Question

What is the pressure when 800N is applied to an area of 0.3m2 ?

Answer 1

Answer:
`2666.67 \text{ (or in 2 sigfigs, }2.7*10^(3))`

Explanation:
`1\text{ }\frac{\text{N}}{\text{m}^2} = 1 \text{ Pa}\\\\P=(F)/(A)\\\\P=\frac{800\text{ N}}{0.3\text{ m}^2} = 2666.\overline6 \text{ N/m}^2 \approx 2666.67 \text{ Pa} \approx 2.7 \text{ kPa}`

Don't know if you need to convert to other units but typically in physics it's left as N/m^2 or Pa.