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A husband and wife have a son with cystic fibrosis. their second child, a daughter, does not. prepare a pedigree for this family

User Elanna
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Pedigrees should demonstrate that the parents have an ordinary overwhelming allele and the latent CF allele and in this way are bearers for CF. Their child is homozygous recessive; their little girl has no less than one duplicate of the ordinary predominant allele.
To have cystic fibrosis the two parents must be a bearer. Each parent passes on one of their qualities to their youngsters; they each have one sound and one cystic fibrosis quality. The youngster with cystic fibrosis gets a cystic fibrosis quality from each parent. The other kid has no less than one sound quality in the event that she doesn't have cystic fibrosis, however she could be a bearer.
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User Chanseok Oh
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