Question

Write the balanced equation for the reaction of aqueous pb(clo3)2 with aqueous nai. include phases.

Answer 1

Step-by-step explanation:

A balanced equation is defined as the equation which contains same number of atoms on both reactant and product side.

For example,
`Pb(ClO_(3))_(2)(aq) + NaI(aq) \rightarrow PbI_(2)(s) + NaClO_(3)(aq)`

So, number of atoms on reactant side are as follows.

• Pb = 1

• 
  `ClO_(3))_(2)` = 2

• Na = 1

• I = 1

Number of atoms on product side are as follows.

• Pb = 1

• 
  `ClO_(3))_(2)` = 1

• Na = 1

• I = 2

Hence, to balance this chemical equation we multiply NaI with 2 on reactant side and we also multiply
`NaClO_(3)` by 2 on product side.

Therefore, the balanced reaction equation will be as follows.

`Pb(ClO_(3))_(2)(aq) + 2NaI(aq) \rightarrow PbI_(2)(s) + 2NaClO_(3)(aq)`

Answer 2

Try a double displacement.

`Pb ^(2+) ClO3^(-) going . to Na{+} , I{-}`

So double displacement is going to form

PbI2 and NaClO3

Put the products in now w/o balancing yet

Pb(ClO3)2 + NaI --> PbI2 + NaClO3

Balance it now and add phase
Pb(ClO3)2 (aq) + 2NaI (ag) --> PbI2 (s) + 2NaClO3 (aq)


And that's it