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How much heat is required to change the temperature of a 15 g aluminum can with 100 g of water from 24.5°C to 55°C?

User VTGroup
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1 Answer

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Heat capacity of aluminium = 0.900 J/g°C
While heat capacity of water = 4.186 J/g°C
Heat = heat gained by water + heat gained by aluminium
Heat gained by water = 100 × 4.186 × 30.5
= 12767.3 Joules
Heat gained by aluminium = 15 × 0.9 × 30.5
= 411.75 Joules
Heat required = 13179.05 Joules or 13.179 kJoules
User Vladimir Korenev
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