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What is the inverse of x/(x-1)

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y= (x)/(x-1) \\ \\ y(x-1)=x \\ xy-y=x \\ xy-x=y \\ x(y-1)=y \\ \\ x= (y)/(y-1) \;\;\;\Rightarrow f^(-1)(x)= (x)/(x-1)
User Steve Wilhelm
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