151k views
4 votes
Find the magnitude and direction angle of v=8(cos135i+sin135j)

User Elcharrua
by
6.0k points

1 Answer

6 votes
The magnitude of the vector will be given by:
v = root ((8cos135) ^ 2 + (8sin135) ^ 2)
v = root ((8) ^ 2 * ((cos135) ^ 2 + (sin135) ^ 2))
v = root ((8) ^ 2 * (1))
v = root ((8) ^ 2)
v = 8
The angle is:
theta = Atan ((8sin135) / (8cos135))
theta = Atan (tan135)
theta = tan135
Answer:
The magnitude and direction angle are:
v = 8
theta = tan135
User Cevin
by
5.4k points