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Describe how to make 1.50 liters of a 0.01 M ammonium chloride solution

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Hello!

To know how many grams of Ammonium Chloride ( a solid) you'll need to make 1.50 L of a 0,01 M solution you'll need to use the definition of molar concentration (M=mol/L) in the following way:


1,50 L* (0,01 mol NH_4Cl)/(1L)* (53,489gNH_4Cl)/(1 mol NH_4Cl)=0,8023 g NH_4Cl

So, you'll need to dissolve 0,8023 g of Ammonium Chloride in 1,5 L of water to make this solution.

Have a nice day!
User Alf Nielsen
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