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The peak intensity of radiation from Mars is about 14,000 nm. What is the average surface temperature of Mars rounded to the nearest whole number?

2 Answers

3 votes

Answer:

T = 206 K

Step-by-step explanation:

As we know by Wein's law of displacement that if we draw all radiations intensity with all possible wavelengths radiated from the object then the wavelength corresponding to maximum intensity of radiation is inversely dependent to the absolute temperature of the object.

So here we can say


\lambda = (b)/(T)

here we know

b = Wein's constant


b = 2.89 * 10^(-3)

now we have


\lambda = 14000 nm

from above equation


14000 * 10^(-9) = (2.89 * 10^(-3))/(T)


T = 206 K

User Inetknght
by
6.0k points
4 votes
If your choices are the following:
blablabla

207 K
406 K
4,857 K
Mars does not emit radiation.

Then the answer is 207 K.
User Ryfterek
by
6.2k points