Question

Factor by grouping. 4x^3 − 16x^2 + 12 − 3x

Answer 1

He first thing that we would really want to consider is that we would definitely want to group this up because it would make things a lot more easier.


`(((4 * (x^3)) - 2^4x^2) + 12) - 3x \\ \\ as \ we \ simplify \ this . . . \\ \\ ((2^2x^3 - 2^4x^2) + 12) - 3x \\ \\ Factoring: \ \boxed{4x^3-16x^2-3x+12 } \\ \\ Factoring: \ 4x^2-3 \\ \\`

Your answer:
`\boxed{\bf{ (4x^2 - 3) *(x - 4)}}`