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In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 60 pound weight if the bar is 24 feet long?

A) 9
B) 15
C) 12

In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located-example-1
User Wrygiel
by
6.2k points

2 Answers

5 votes

Answer:

15

Explanation:

User Tayacan
by
6.6k points
5 votes

Answer:

15 feet

Explanation:

Given : In this fulcrum, the weights are perfectly balanced.

To Find: How far must the fulcrum be located from the 60 pound weight if the bar is 24 feet long?

Solution:

To make the weights perfectly balanced torque must be equal


Torque = Force * d

Where
Force = Mass * Acceleration

Let a be the acceleration

d= Distance between the pivot and the acting point.

Let x be the distance from 60 pound weight where fulcrum is located

Since we are given that Length of bar = 24 feet.

So,Distance of fulcrum from 100 pound weight = 24-x

Now torque for 60 pound weight :


Torque = 60a * x

Now torque for 100 pound weight.


Torque =100a * (24-x)

Now to maintain the equilibrium i.e. To make the weights perfectly balanced


60a * x =100a * (24-x)


60x = 2400-100x


160x = 2400


x = (2400)/(160)


x = 15

Hence The fulcrum must be located 15 feet from the 60 pound weight if the bar is 24 feet long.

User Cathy Ha
by
5.4k points