Question

An 18 liter container holds 16.00 grams of oxygen gas (o2 at 45 °c. what is the pressure in the container?

Answer 1

Hello!

The pressure of an 18 L container which holds 16,00 grams of oxygen gas (O₂) at 45 °C is 0,725 atm

To solve this problem we first need to set up the data in the appropriate units to input it in the Ideal Gas Law.

a) 16 g of Oxygen gas to moles of oxygen gas:


`16gO_2* (1 mol O_2)/(32gO_2)=0,5 mol O_2`

b) 45 °C to K


`K=$^(\circ)$C + 273,15 = 45 $^(\circ)$C + 273.15=318,15 K`

Now, we clear the Ideal Gas Equation for P, and solve it:


`P*V=n*R*T \\ \\ P= (n*R*T)/(V)= ((0,5mol)*(0,082 (L*atm)/(mol*K))* (318,15 K))/(18 L)= 0,725 atm`

Have a nice day!