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Zephyr · Answer 1 · 2019-03-04T00:38:21+0000

The given equation is f(x) = 29. The graph is a horizontal line, which has no vertex. Perhaps you intend
.. f(x) = 5x^2 +20x -16
.. = 5(x^2 +4x +4) -16 -20
.. = 5(x +2)^2 -36

The vertex is (-2, -36)

What is the vertex of f(x)=5^2+20-16-example-1

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