A large spherical balloon

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asked Sep 9, 2019 86.1k views

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Surfmuggle · Answer 1 · 2019-09-15T11:54:16+0000

V = (4/3)π*r^3
V' = 4π*r^2*r'
600 cm^3/min = 4π(30 cm)^2*r'

r' = (600 cm^3/min)/(4π(30 cm)^2) = 1/(6π) cm/min

The rate of change of radius is about 0.05305 cm/min.

A large spherical balloon

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