Question

A weight lifter holds 100 kg above his head for 5 seconds. What is the work done on the weights?

Answer 1

That's actually a trick question. There would be no work done on the weights because the weight lifter is holding it with no net force change. Also, the formula for work is W=Fd. There is no Δx distance in this instance. I hope this helps! Have a good day.

Answer 2

Hello!

Work is force times distance times the cos of the angle between the two vectors. In this situation there is no distance covered or change in distance, therefore no work can be done. It does take energy from that person to hold the weight, but no work is actually done by holding anything stagnant.

Any questions please just ask! Thanks!