Question

An air mass of volume 6.5 x 10 to the fifth L starts at sea level, where the pressure is 775 mm HG. It rises up a mountain where the pressure is 622 mm HG. Assuming no change in temperature, what is the volume of the air mass?

Answer 1

From Boyle's law the volume of a fixed mass of a gas is inversely proportional to temperature at constant absolute temperature.
Thus, Vα1/P
= V = k/P where k is a constant
P1V1=P2V2
Therefore; V2 = P1V1/P2
= ( 6.0 ×10^-5 × 775) /622
= 7.476 × 10^-5 L
Hence, the new volume of the air mass is 7.476 × 10^-5 L