Question

A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6. Find the total area of the pyramid.

Answer 1

Surface Area of Pyramid:=72
HexagonalArea of Base: [(6/2) as]Surface Area of Pyramid: [3as + 3sl]Volume of Pyramid: [abh ]Where,As = area of side lengthsl= slant heightabh area of base * height

Answer 2

Area of hexagonal pyramid = 113.57 unit²

Explanation:

Area of hexagonal pyramid = Area of base + Area of six triangular slanting face.

Area of base = 6 x Area of equilateral triangle with side 4.

`\texttt{Area of base = }6* (√(3))/(4)a^2=6* (√(3))/(4)* 4^2=24√(3)unit^2`

`\texttt{Area of six triangular slanting face = }6* (1)/(2)* ah=3* 4* 6=72unit^2`

Area of hexagonal pyramid = Area of base + Area of six triangular slanting face.

Area of hexagonal pyramid = 24√3 + 72 = 113.57 unit²